Cyclododecanol to cyclododecanone. Oxidation of Cyclododecanol 2022-11-02
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Cyclododecanol and cyclododecanone are both compounds that belong to the same chemical family known as cycloalkanols and cycloalkanones, respectively. These compounds are characterized by the presence of a cyclic ring structure containing 12 carbon atoms and a hydroxyl group (-OH) or a carbonyl group (-C=O) attached to one of the carbon atoms in the ring.
Cyclododecanol is a white, waxy solid with a melting point of around 47°C. It is soluble in water and has a high boiling point due to the presence of the hydroxyl group, which can hydrogen bond with other molecules. Cyclododecanol is commonly used as a raw material in the production of detergents, surfactants, and emulsifiers, due to its ability to dissolve in water and form stable emulsions with oils and other non-polar substances. It is also used as a lubricant and a plasticizer in the manufacturing of rubber and other polymers.
On the other hand, cyclododecanone is a colorless liquid with a sweet, fruity odor. It has a lower boiling point than cyclododecanol due to the absence of the hydroxyl group, which reduces the possibility of hydrogen bonding. Cyclododecanone is produced through the oxidation of cyclododecanol, which involves the removal of the hydroxyl group and the formation of the carbonyl group. Cyclododecanone is used as a intermediate in the synthesis of fragrances, flavors, and pharmaceuticals, as well as in the production of resins and plasticizers.
In conclusion, cyclododecanol and cyclododecanone are two closely related compounds that differ in their physical and chemical properties due to the presence or absence of a hydroxyl group. Cyclododecanol is a waxy solid used as a raw material in the production of detergents and other industrial products, while cyclododecanone is a liquid used as a intermediate in the synthesis of fragrances and other chemical compounds.
Oxidation of an Alcohol
Redox reactions tend to mean the loss or gain of electrons, but in Organic Chemistry it refers to the addition or reduction of an Oxygen bond. The IR peaks indicated that the alcohol had changed into a ketone. Along with the difference in mass, the final IR results showed a change in the chemical. . Oxidation from -2 to 0 e. Results: Chemical Weight Cyclododecanol. The experimental melting point was only 3 degrees off of the actual melting point, but there were still impurities in our final product.
Oxidation of Cyclododecanol CHEM 341 Introduction: The purpose of this lab was to oxidize Cyclododecanol to form Cyclododecanone by using dehydration to remove a functional group off of Cyclododecanol and replace it with a ketone to form Cyclododecanone. Oxidation from +1 to + c. After performing the experiment, it was seen that the final mass of the pure product was less than the initial mass of the dry alcohol. There could be potential human error which resulted in a lower %recovery. Recrystallization: -Recrystallize the crude cyclododecanone with a mixture of methanol and water. There were no real surprises in the results and it was a very successful experiment. When this happens, we can see this change in the Fourier-transform infrared spectroscopy FTIR , which shows us what functional groups there are in a compound.
Allow mixture to reflux for 15min. IR Spectroscopy: -Obtain a salt plate and place a small spatula tip of your product in a test tube. Reduction from -2 to - d. Obtain a melting point of the final product. After purifying the solid, and vacuum filtering again, the mass decreased. Our FT-IR gave us peaks at 1700 and 2800 and this was expected because of the double bonded Oxygen and single bonded Carbon Conclusion: The results of this experiment seemed to be successful, with only some minor impurities in our sample, it gave us near perfect results. The species that is oxidized loses electrons and the species that is reduced gains electrons.
Obtain a melting point of the final product. The experimental melting point was only 3 degrees off of the actual melting point, but there were still impurities in our final product. It would not be expected to give a positive iodoform test because the product cyclododecanone does not contain a methyl ketone group and a positive iodoform test should contain a methyl ketone. There could be potential human error which resulted in a lower %recovery. Our FT-IR gave us peaks at 1700 and 2800 and this was expected because of the double bonded Oxygen and single bonded Carbon Conclusion: The results of this experiment seemed to be successful, with only some minor impurities in our sample, it gave us near perfect results. Test the solution with iodine test paper. There were no real surprises in the results and it was a very successful experiment.
In our reaction, NaClO is the oxidizing agent and Cyclododecanol is being reduced. Add a stir bar and position the flask inside a cloth heating mantle above a stir plate. Attach the water hoses and secure all parts in place with clamps. Oxidation from -3 to -. Theory: -Filter through a funnel with flter paper and remove the solvent by rotary evaporation. Theory: The reaction taking place is a redox reaction, where one species is oxidized and one is reduced.
Oxidation of Cyclododecanol CHEM 341 Introduction: The purpose of this lab was to oxidize Cyclododecanol to form Cyclododecanone by using dehydration to remove a functional group off of Cyclododecanol and replace it with a ketone to form Cyclododecanone. After vacuum filtering the first time, the mass increased. Some modifications were made. Remove aqueous layer and further extract extra aqueous layers. Experimental: Chemicals: Name Structure Physical Cyclododecanol Solid, 278°C, 184. . .
